NEW INTERVIEW QUESTIONS.COM QUANTITATIVE INTERVIEW QUESTIONS DETAILS

Add to My Questions | Forward | Print

Question

A man bought a horse and a cart. If he sold the horse at 10 % loss and the cart at 20 % gain, he would not lose anything, but if he sold the horse at 5% loss and the cart at 5% gain, he would lose Rs. 10 in the bargain. The amount paid by him was Rs.- _______ for the horse and Rs.________ for the cart.

Answer

Cost price of horse = Rs. 400 & the cost price of cart = 200.Explanation:-Let x be the cost price of the horse and y be the cost price of the cart.In the first sale there is no loss or profit. (i.e.) The loss obtained is equal to the gain.Therefore (10/100) * x = (20/100) * yX = 2 * y -----------------(1)In the second sale, he lost Rs. 10. (i.e.) The loss is greater than the profit by Rs. 10.Therefore (5 / 100) * x = (5 / 100) * y + 10 -------(2)Substituting (1) in (2) we get(10 / 100) * y = (5 / 100) * y + 10(5 / 100) * y = 10y = 200From (1) 2 * 200 = x = 400. 200 and 400 is actual cost but the question is after the second sale what is the amount given by him... it is 210(with 5%gain)and 380(5%loss) so the money lost by him is Rs10. Answered By: ganesh    Date: 5/16/2008 © NewInterviewQuestions.com

Answer:*
Name:*
Email Address:*
Verification Code	Not readable? Load New Code
Enter the above shown code:*

Category	Quantitative Interview Questions
Rating	(0.0) By 0 users
Added	7/12/2005
Views	154134
Rate it!	* * * * * * * * * * * * * * *
Free Offers:	300 Free Magazines for you. No credit card required. No Shipping Charges. Absolutely Free for 1 Year.

Please Note: We keep on updating better answers to this site. Subscribe to our newsletter to get notified when better answer is posted.

Notify me when better answer is posted!
Email: