|
|
NEW INTERVIEW QUESTIONS.COM
QUANTITATIVE INTERVIEW QUESTIONS DETAILS
NewInterviewQuestions.com - Home for World's Largest Interview Questions Website.
A D V E R T I S E M E N T
Question |
Five farmers have 7, 9, 11, 13 & 14 apple trees, respectively in their orchards. Last year, each of them discovered that every tree in their own orchard bore exactly the same number of apples. Further, if the third farmer gives one apple to the first, and the fifth gives three to each of the second and the fourth, they would all have exactly the same number of apples. What were the yields per tree in the orchards of the third and fourth farmers?
|
Answer
|
11 & 9 apples per tree.Explanation:Let a, b, c, d & e be the total number of apples bored per year in A, B, C, D &E ?s orchard. Given that a + 1 = b + 3 = c - 1 = d + 3 = e - 6But the question is to find the number of apples bored per tree in C and D ?s orchard.If is enough to consider c - 1 = d + 3.Since the number of trees in C?s orchard is 11 and that of D?s orchard is 13.Let x and y be the number of apples bored per tree in C & d ?s orchard respectively.Therefore 11 x - 1 = 13 y + 3By trial and error method, we get the value for x and y as 11 and 9.
7+9+11+13+14
8+12+11+16+2
9.8
Hence they have
Answered By: Parul Date: 4/24/2008
© NewInterviewQuestions.com
|
If you have the better answer, than send it to us. We will display your answer after the approval.
Rate the above answer. Help us to know about the answer.
Please Note: We keep on updating better answers to this site. Subscribe to our newsletter to get notified when better answer is posted.
A D V E R T I S E M E N T
|
|
|
Latest 10 Answers
|
Hub supports broadcasting.But switch supports unicasting and broadcasting.So many network system using switch.
|
Between 2GB And 4GB.
|
100000
|
A LIST OF BALANCES OF A/CS OF LEDGERS IS CALLED A TRIAL BALANCE.
|
log6=e^6 and log5=e^5 then log(a+b)=log(a*b).e^(6*5)=e^30.
so,log30 is answer.
|
tn=a+(n-1)d.
series is 112,126,140,154......994.
a=112,tn=994,d=14.sustitute will get n=64.
sn=n/2{first term+last term),sn=64/2{112+994},sn=35392
|
1.Employee Details
2.Patient details
3.Hospital Location
4.Ambulance Service
5.operation rooms
6.No of Staff doctors,nurse etc.
5.Availabilty of Good service
|
Data reader is to read the data .It can read only one row data at a time.
Data adapter acts as a bridge between Database and data set.It is used to maintain the connection and it reads whole data at a time.
|
# include
#include
void main()
{
clrscr();
printf("\n "xxx"\n");
getch();
}
|
variable is a place where we can store different type of value.
In other word,in computer memory the space where we store constant value i.e.we can say the home of constant in memory.
|
|